(2x+1)^2+3=21

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Solution for (2x+1)^2+3=21 equation: 



(2x+1)^2+3=21

We move all terms to the left:

(2x+1)^2+3-(21)=0

We add all the numbers together, and all the variables

(2x+1)^2-18=0

We move all terms containing x to the left, all other terms to the right

(2x+1)^2=18

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